13380113 has 2 divisors, whose sum is σ = 13380114. Its totient is φ = 13380112.

The previous prime is 13380067. The next prime is 13380119. The reversal of 13380113 is 31108331.

It is a happy number.

13380113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13010449 + 369664 = 3607^2 + 608^2 .

It is an emirp because it is prime and its reverse (31108331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13380113 - 2¹⁴ = 13363729 is a prime.

It is not a weakly prime, because it can be changed into another prime (13380119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6690056 + 6690057.

It is an arithmetic number, because the mean of its divisors is an integer number (6690057).

Almost surely, 2^13380113 is an apocalyptic number.

It is an amenable number.

13380113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13380113 is an equidigital number, since it uses as much as digits as its factorization.

13380113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 20.

The square root of 13380113 is about 3657.8836777569. The cubic root of 13380113 is about 237.4032137485.

Adding to 13380113 its reverse (31108331), we get a palindrome (44488444).

The spelling of 13380113 in words is "thirteen million, three hundred eighty thousand, one hundred thirteen".