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13380499130093 is a prime number
BaseRepresentation
bin1100001010110110001111…
…1001011100011011101101
31202101011101222202001210022
43002231203321130123231
53223211230234130333
644242525541251525
72550465146010314
oct302554371343355
952334358661708
1013380499130093
114299701a25987
121601292103ba5
13760a1115ac84
1434389630d27b
151830ce059c98
hexc2b63e5c6ed

13380499130093 has 2 divisors, whose sum is σ = 13380499130094. Its totient is φ = 13380499130092.

The previous prime is 13380499130087. The next prime is 13380499130129. The reversal of 13380499130093 is 39003199408331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8914153692964 + 4466345437129 = 2985658^2 + 2113373^2 .

It is a cyclic number.

It is not a de Polignac number, because 13380499130093 - 210 = 13380499129069 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13380499133093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6690249565046 + 6690249565047.

It is an arithmetic number, because the mean of its divisors is an integer number (6690249565047).

Almost surely, 213380499130093 is an apocalyptic number.

It is an amenable number.

13380499130093 is a deficient number, since it is larger than the sum of its proper divisors (1).

13380499130093 is an equidigital number, since it uses as much as digits as its factorization.

13380499130093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1889568, while the sum is 53.

The spelling of 13380499130093 in words is "thirteen trillion, three hundred eighty billion, four hundred ninety-nine million, one hundred thirty thousand, ninety-three".