Base | Representation |
---|---|
bin | 1100001010111001000011… |
… | …0011100101101001101011 |
3 | 1202101020100111110202122012 |
4 | 3002232100303211221223 |
5 | 3223214301124212312 |
6 | 44243132414150135 |
7 | 2550522625103261 |
oct | 302562063455153 |
9 | 52336314422565 |
10 | 13381252569707 |
11 | 4299a59255250 |
12 | 16014624b234b |
13 | 760b0128b229 |
14 | 3439283d8431 |
15 | 183125286322 |
hex | c2b90ce5a6b |
13381252569707 has 16 divisors (see below), whose sum is σ = 14657671772640. Its totient is φ = 12114919449600.
The previous prime is 13381252569691. The next prime is 13381252569721. The reversal of 13381252569707 is 70796525218331.
13381252569707 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13381252569707 - 24 = 13381252569691 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13381252569407) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 399707 + ... + 5188667.
It is an arithmetic number, because the mean of its divisors is an integer number (916104485790).
Almost surely, 213381252569707 is an apocalyptic number.
13381252569707 is a deficient number, since it is larger than the sum of its proper divisors (1276419202933).
13381252569707 is a wasteful number, since it uses less digits than its factorization.
13381252569707 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4790014.
The product of its (nonzero) digits is 19051200, while the sum is 59.
The spelling of 13381252569707 in words is "thirteen trillion, three hundred eighty-one billion, two hundred fifty-two million, five hundred sixty-nine thousand, seven hundred seven".
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