Base | Representation |
---|---|
bin | 10011011110001111100… |
… | …101100001111001111111 |
3 | 11201220222112122201120102 |
4 | 103132033211201321333 |
5 | 133411004303343101 |
6 | 2502422413511315 |
7 | 165451310464142 |
oct | 23361745417177 |
9 | 4656875581512 |
10 | 1338143809151 |
11 | 47655a327606 |
12 | 1974117a253b |
13 | 99256744706 |
14 | 48aa3414059 |
15 | 24c1c9a486b |
hex | 1378f961e7f |
1338143809151 has 2 divisors, whose sum is σ = 1338143809152. Its totient is φ = 1338143809150.
The previous prime is 1338143809109. The next prime is 1338143809169. The reversal of 1338143809151 is 1519083418331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1338143809151 - 226 = 1338076700287 is a prime.
It is a super-2 number, since 2×13381438091512 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1338143809096 and 1338143809105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1338143809351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 669071904575 + 669071904576.
It is an arithmetic number, because the mean of its divisors is an integer number (669071904576).
Almost surely, 21338143809151 is an apocalyptic number.
1338143809151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1338143809151 is an equidigital number, since it uses as much as digits as its factorization.
1338143809151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 311040, while the sum is 47.
The spelling of 1338143809151 in words is "one trillion, three hundred thirty-eight billion, one hundred forty-three million, eight hundred nine thousand, one hundred fifty-one".
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