Base | Representation |
---|---|
bin | 111110010011111111… |
… | …0111011110001001011 |
3 | 110210101210010221001002 |
4 | 1330213332323301023 |
5 | 4143023041422324 |
6 | 141250151245215 |
7 | 12445024664441 |
oct | 1744776736113 |
9 | 423353127032 |
10 | 133814795339 |
11 | 51828a66355 |
12 | 21b2637980b |
13 | c80731c394 |
14 | 6695dacb91 |
15 | 3732c033ae |
hex | 1f27fbbc4b |
133814795339 has 2 divisors, whose sum is σ = 133814795340. Its totient is φ = 133814795338.
The previous prime is 133814795287. The next prime is 133814795341. The reversal of 133814795339 is 933597418331.
It is a strong prime.
It is an emirp because it is prime and its reverse (933597418331) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133814795339 is a prime.
It is a super-2 number, since 2×1338147953392 (a number of 23 digits) contains 22 as substring.
Together with 133814795341, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (133814791339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66907397669 + 66907397670.
It is an arithmetic number, because the mean of its divisors is an integer number (66907397670).
Almost surely, 2133814795339 is an apocalyptic number.
133814795339 is a deficient number, since it is larger than the sum of its proper divisors (1).
133814795339 is an equidigital number, since it uses as much as digits as its factorization.
133814795339 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 7348320, while the sum is 56.
The spelling of 133814795339 in words is "one hundred thirty-three billion, eight hundred fourteen million, seven hundred ninety-five thousand, three hundred thirty-nine".
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