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13381508183 is a prime number
BaseRepresentation
bin11000111011001100…
…11001110001010111
31021112120200001022012
430131212121301113
5204401131230213
610051500054435
7652414641251
oct143546316127
937476601265
1013381508183
11574757017a
12271553441b
13135343a4a4
1490d2b8cd1
15534bb14a8
hex31d999c57

13381508183 has 2 divisors, whose sum is σ = 13381508184. Its totient is φ = 13381508182.

The previous prime is 13381508167. The next prime is 13381508213. The reversal of 13381508183 is 38180518331.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13381508183 - 24 = 13381508167 is a prime.

It is a super-2 number, since 2×133815081832 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13381508183.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13381508113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6690754091 + 6690754092.

It is an arithmetic number, because the mean of its divisors is an integer number (6690754092).

Almost surely, 213381508183 is an apocalyptic number.

13381508183 is a deficient number, since it is larger than the sum of its proper divisors (1).

13381508183 is an equidigital number, since it uses as much as digits as its factorization.

13381508183 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69120, while the sum is 41.

The spelling of 13381508183 in words is "thirteen billion, three hundred eighty-one million, five hundred eight thousand, one hundred eighty-three".