Base | Representation |
---|---|
bin | 111110010100101110… |
… | …1101110111011111001 |
3 | 110210110111220111100212 |
4 | 1330221131232323321 |
5 | 4143100422141312 |
6 | 141252440040505 |
7 | 12445446136616 |
oct | 1745135567371 |
9 | 423414814325 |
10 | 133839646457 |
11 | 51840a9a370 |
12 | 21b32763135 |
13 | c80c51089a |
14 | 66993db50d |
15 | 3734eb1822 |
hex | 1f2976eef9 |
133839646457 has 4 divisors (see below), whose sum is σ = 146006887056. Its totient is φ = 121672405860.
The previous prime is 133839646439. The next prime is 133839646459. The reversal of 133839646457 is 754646938331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133839646457 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 133839646396 and 133839646405.
It is not an unprimeable number, because it can be changed into a prime (133839646459) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6083620283 + ... + 6083620304.
It is an arithmetic number, because the mean of its divisors is an integer number (36501721764).
Almost surely, 2133839646457 is an apocalyptic number.
It is an amenable number.
133839646457 is a deficient number, since it is larger than the sum of its proper divisors (12167240599).
133839646457 is a wasteful number, since it uses less digits than its factorization.
133839646457 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12167240598.
The product of its digits is 39191040, while the sum is 59.
The spelling of 133839646457 in words is "one hundred thirty-three billion, eight hundred thirty-nine million, six hundred forty-six thousand, four hundred fifty-seven".
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