Base | Representation |
---|---|
bin | 111110010100101111… |
… | …1101011011000111111 |
3 | 110210110112212101122002 |
4 | 1330221133223120333 |
5 | 4143101034444343 |
6 | 141252455012515 |
7 | 12445453362044 |
oct | 1745137533077 |
9 | 423415771562 |
10 | 133840156223 |
11 | 51841308364 |
12 | 21b3296a13b |
13 | c80c65b917 |
14 | 66994d11cb |
15 | 37350628b8 |
hex | 1f297eb63f |
133840156223 has 4 divisors (see below), whose sum is σ = 133840943040. Its totient is φ = 133839369408.
The previous prime is 133840156217. The next prime is 133840156243. The reversal of 133840156223 is 322651048331.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 322651048331 = 1523 ⋅211852297.
It is a cyclic number.
It is not a de Polignac number, because 133840156223 - 24 = 133840156207 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133840156213) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20303 + ... + 517776.
It is an arithmetic number, because the mean of its divisors is an integer number (33460235760).
Almost surely, 2133840156223 is an apocalyptic number.
133840156223 is a deficient number, since it is larger than the sum of its proper divisors (786817).
133840156223 is an equidigital number, since it uses as much as digits as its factorization.
133840156223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 786816.
The product of its (nonzero) digits is 103680, while the sum is 38.
The spelling of 133840156223 in words is "one hundred thirty-three billion, eight hundred forty million, one hundred fifty-six thousand, two hundred twenty-three".
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