1338401686441 has 2 divisors, whose sum is σ = 1338401686442. Its totient is φ = 1338401686440.

The previous prime is 1338401686397. The next prime is 1338401686451. The reversal of 1338401686441 is 1446861048331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 760071856041 + 578329830400 = 871821^2 + 760480^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1338401686441 is a prime.

It is a super-2 number, since 2×1338401686441² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1338401686451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 669200843220 + 669200843221.

It is an arithmetic number, because the mean of its divisors is an integer number (669200843221).

Almost surely, 2^{1338401686441} is an apocalyptic number.

It is an amenable number.

1338401686441 is a deficient number, since it is larger than the sum of its proper divisors (1).

1338401686441 is an equidigital number, since it uses as much as digits as its factorization.

1338401686441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1327104, while the sum is 49.

It can be divided in two parts, 133840 and 1686441, that added together give a palindrome (1820281).

The spelling of 1338401686441 in words is "one trillion, three hundred thirty-eight billion, four hundred one million, six hundred eighty-six thousand, four hundred forty-one".