Search a number
-
+
13388271364789 is a prime number
BaseRepresentation
bin1100001011010011001100…
…1010001010101010110101
31202101220110122120111102121
43002310303022022222311
53223323134432133124
644250253103235541
72551161562632556
oct302646312125265
952356418514377
1013388271364789
1142a1a30176942
1216028a0ba8bb1
1376167c445009
14343dd264832d
151833d65642e4
hexc2d3328aab5

13388271364789 has 2 divisors, whose sum is σ = 13388271364790. Its totient is φ = 13388271364788.

The previous prime is 13388271364763. The next prime is 13388271364801. The reversal of 13388271364789 is 98746317288331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9808766291025 + 3579505073764 = 3131895^2 + 1891958^2 .

It is an emirp because it is prime and its reverse (98746317288331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13388271364789 - 29 = 13388271364277 is a prime.

It is a super-2 number, since 2×133882713647892 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13388271364729) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6694135682394 + 6694135682395.

It is an arithmetic number, because the mean of its divisors is an integer number (6694135682395).

Almost surely, 213388271364789 is an apocalyptic number.

It is an amenable number.

13388271364789 is a deficient number, since it is larger than the sum of its proper divisors (1).

13388271364789 is an equidigital number, since it uses as much as digits as its factorization.

13388271364789 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 292626432, while the sum is 70.

The spelling of 13388271364789 in words is "thirteen trillion, three hundred eighty-eight billion, two hundred seventy-one million, three hundred sixty-four thousand, seven hundred eighty-nine".