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13388697481 is a prime number
BaseRepresentation
bin11000111100000011…
…10100111110001001
31021120002012022011111
430132001310332021
5204410001304411
610052314130321
7652533023305
oct143601647611
937502168144
1013388697481
115750630645
122717a209a1
131354a86903
1491022ad05
15535631721
hex31e074f89

13388697481 has 2 divisors, whose sum is σ = 13388697482. Its totient is φ = 13388697480.

The previous prime is 13388697437. The next prime is 13388697523. The reversal of 13388697481 is 18479688331.

13388697481 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11767910400 + 1620787081 = 108480^2 + 40259^2 .

It is a cyclic number.

It is not a de Polignac number, because 13388697481 - 215 = 13388664713 is a prime.

It is a super-2 number, since 2×133886974812 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13388692481) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6694348740 + 6694348741.

It is an arithmetic number, because the mean of its divisors is an integer number (6694348741).

Almost surely, 213388697481 is an apocalyptic number.

It is an amenable number.

13388697481 is a deficient number, since it is larger than the sum of its proper divisors (1).

13388697481 is an equidigital number, since it uses as much as digits as its factorization.

13388697481 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6967296, while the sum is 58.

The spelling of 13388697481 in words is "thirteen billion, three hundred eighty-eight million, six hundred ninety-seven thousand, four hundred eighty-one".