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133889545603 = 11103118172591
BaseRepresentation
bin111110010110001110…
…0000101010110000011
3110210120222210122010101
41330230130011112003
54143201210424403
6141301421343231
712446623234312
oct1745434052603
9423528718111
10133889545603
1151867181330
1221b47407b17
13c8199620c8
1466a1caa279
15373956b71d
hex1f2c705583

133889545603 has 8 divisors (see below), whose sum is σ = 147479394816. Its totient is φ = 120536041800.

The previous prime is 133889545589. The next prime is 133889545663. The reversal of 133889545603 is 306545988331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 133889545603 - 29 = 133889545091 is a prime.

It is a super-3 number, since 3×1338895456033 (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133889545663) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 59085163 + ... + 59087428.

It is an arithmetic number, because the mean of its divisors is an integer number (18434924352).

Almost surely, 2133889545603 is an apocalyptic number.

133889545603 is a deficient number, since it is larger than the sum of its proper divisors (13589849213).

133889545603 is a wasteful number, since it uses less digits than its factorization.

133889545603 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 118172705.

The product of its (nonzero) digits is 9331200, while the sum is 55.

The spelling of 133889545603 in words is "one hundred thirty-three billion, eight hundred eighty-nine million, five hundred forty-five thousand, six hundred three".

Divisors: 1 11 103 1133 118172591 1299898501 12171776873 133889545603