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133943497 is a prime number
BaseRepresentation
bin1111111101111…
…01000011001001
3100100001000221021
413332331003021
5233242142442
621142512441
73214333552
oct776750311
9310030837
10133943497
1169675806
1238a35721
132199970c
1413b09329
15bb5be67
hex7fbd0c9

133943497 has 2 divisors, whose sum is σ = 133943498. Its totient is φ = 133943496.

The previous prime is 133943479. The next prime is 133943507. The reversal of 133943497 is 794349331.

Together with previous prime (133943479) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 124634896 + 9308601 = 11164^2 + 3051^2 .

It is a cyclic number.

It is not a de Polignac number, because 133943497 - 211 = 133941449 is a prime.

It is not a weakly prime, because it can be changed into another prime (133943477) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66971748 + 66971749.

It is an arithmetic number, because the mean of its divisors is an integer number (66971749).

Almost surely, 2133943497 is an apocalyptic number.

It is an amenable number.

133943497 is a deficient number, since it is larger than the sum of its proper divisors (1).

133943497 is an equidigital number, since it uses as much as digits as its factorization.

133943497 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 244944, while the sum is 43.

The square root of 133943497 is about 11573.3960875795. The cubic root of 133943497 is about 511.6510594939.

The spelling of 133943497 in words is "one hundred thirty-three million, nine hundred forty-three thousand, four hundred ninety-seven".