Base | Representation |
---|---|
bin | 11110011101001100101100… |
… | …110011111101010000110110 |
3 | 122120021021221020111011020200 |
4 | 132131030230303331100312 |
5 | 120024100243100100014 |
6 | 1152514451521141330 |
7 | 40133262516403323 |
oct | 3635145463752066 |
9 | 576237836434220 |
10 | 133947896878134 |
11 | 39752a908561a9 |
12 | 13033bbb78a846 |
13 | 599830399c0a1 |
14 | 251118174bb4a |
15 | 107445b22ba09 |
hex | 79d32ccfd436 |
133947896878134 has 24 divisors (see below), whose sum is σ = 290456203189152. Its totient is φ = 44613028197360.
The previous prime is 133947896878121. The next prime is 133947896878241. The reversal of 133947896878134 is 431878698749331.
133947896878134 is a `hidden beast` number, since 1 + 3 + 3 + 9 + 478 + 9 + 6 + 8 + 7 + 8 + 134 = 666.
133947896878134 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3022540729 + ... + 3022585044.
It is an arithmetic number, because the mean of its divisors is an integer number (12102341799548).
Almost surely, 2133947896878134 is an apocalyptic number.
133947896878134 is an abundant number, since it is smaller than the sum of its proper divisors (156508306311018).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133947896878134 is a wasteful number, since it uses less digits than its factorization.
133947896878134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6045127012 (or 6045127009 counting only the distinct ones).
The product of its digits is 5267275776, while the sum is 81.
The spelling of 133947896878134 in words is "one hundred thirty-three trillion, nine hundred forty-seven billion, eight hundred ninety-six million, eight hundred seventy-eight thousand, one hundred thirty-four".
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