13397000131 has 2 divisors, whose sum is σ = 13397000132. Its totient is φ = 13397000130.

The previous prime is 13397000129. The next prime is 13397000261. The reversal of 13397000131 is 13100079331.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13397000131 - 2¹ = 13397000129 is a prime.

It is a super-2 number, since 2×13397000131² (a number of 21 digits) contains 22 as substring.

Together with 13397000129, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 13397000131.

It is not a weakly prime, because it can be changed into another prime (13397010131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6698500065 + 6698500066.

It is an arithmetic number, because the mean of its divisors is an integer number (6698500066).

Almost surely, 2^13397000131 is an apocalyptic number.

13397000131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13397000131 is an equidigital number, since it uses as much as digits as its factorization.

13397000131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1701, while the sum is 28.

Adding to 13397000131 its reverse (13100079331), we get a palindrome (26497079462).

The spelling of 13397000131 in words is "thirteen billion, three hundred ninety-seven million, one hundred thirty-one", and thus it is an aban number.