Base | Representation |
---|---|
bin | 11000111101000110… |
… | …00100101100100001 |
3 | 1021120200121002010012 |
4 | 30132203010230201 |
5 | 204414214201031 |
6 | 10053225014305 |
7 | 653000062034 |
oct | 143643045441 |
9 | 37520532105 |
10 | 13397412641 |
11 | 5755543458 |
12 | 271a924395 |
13 | 1356818702 |
14 | 91145901b |
15 | 5362a3b2b |
hex | 31e8c4b21 |
13397412641 has 2 divisors, whose sum is σ = 13397412642. Its totient is φ = 13397412640.
The previous prime is 13397412617. The next prime is 13397412643. The reversal of 13397412641 is 14621479331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13157007616 + 240405025 = 114704^2 + 15505^2 .
It is an emirp because it is prime and its reverse (14621479331) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13397412641 is a prime.
It is a Sophie Germain prime.
Together with 13397412643, it forms a pair of twin primes.
It is a Chen prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (13397412643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6698706320 + 6698706321.
It is an arithmetic number, because the mean of its divisors is an integer number (6698706321).
Almost surely, 213397412641 is an apocalyptic number.
It is an amenable number.
13397412641 is a deficient number, since it is larger than the sum of its proper divisors (1).
13397412641 is an equidigital number, since it uses as much as digits as its factorization.
13397412641 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 108864, while the sum is 41.
The spelling of 13397412641 in words is "thirteen billion, three hundred ninety-seven million, four hundred twelve thousand, six hundred forty-one".
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