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133990706111533 is a prime number
BaseRepresentation
bin11110011101110100100100…
…011100001110010000101101
3122120102101102200121112111121
4132131310210130032100231
5120030300431231032113
61152550251451420541
740136336415030055
oct3635644434162055
9576371380545447
10133990706111533
113976a159518937
1213040368454751
13599c366a6251b
142513283064565
151075614673e8d
hex79dd2470e42d

133990706111533 has 2 divisors, whose sum is σ = 133990706111534. Its totient is φ = 133990706111532.

The previous prime is 133990706111459. The next prime is 133990706111543. The reversal of 133990706111533 is 335111607099331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 87738778142404 + 46251927969129 = 9366898^2 + 6800877^2 .

It is a cyclic number.

It is not a de Polignac number, because 133990706111533 - 233 = 133982116176941 is a prime.

It is a super-2 number, since 2×1339907061115332 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133990706111543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66995353055766 + 66995353055767.

It is an arithmetic number, because the mean of its divisors is an integer number (66995353055767).

Almost surely, 2133990706111533 is an apocalyptic number.

It is an amenable number.

133990706111533 is a deficient number, since it is larger than the sum of its proper divisors (1).

133990706111533 is an equidigital number, since it uses as much as digits as its factorization.

133990706111533 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1377810, while the sum is 52.

The spelling of 133990706111533 in words is "one hundred thirty-three trillion, nine hundred ninety billion, seven hundred six million, one hundred eleven thousand, five hundred thirty-three".