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133998618383117 is a prime number
BaseRepresentation
bin11110011101111011111100…
…000011001001001100001101
3122120110010212002221120122022
4132131323330003021030031
5120030413132301224432
61152554040535055525
740140036452155205
oct3635737403111415
9576403762846568
10133998618383117
1139772549816664
12130419b62115a5
1359a002806a627
1425137d3c13405
1510759290e0b12
hex79defc0c930d

133998618383117 has 2 divisors, whose sum is σ = 133998618383118. Its totient is φ = 133998618383116.

The previous prime is 133998618383107. The next prime is 133998618383143. The reversal of 133998618383117 is 711383816899331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 133651657329961 + 346961053156 = 11560781^2 + 589034^2 .

It is a cyclic number.

It is not a de Polignac number, because 133998618383117 - 216 = 133998618317581 is a prime.

It is a super-2 number, since 2×1339986183831172 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133998618383107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66999309191558 + 66999309191559.

It is an arithmetic number, because the mean of its divisors is an integer number (66999309191559).

Almost surely, 2133998618383117 is an apocalyptic number.

It is an amenable number.

133998618383117 is a deficient number, since it is larger than the sum of its proper divisors (1).

133998618383117 is an equidigital number, since it uses as much as digits as its factorization.

133998618383117 is an evil number, because the sum of its binary digits is even.

The product of its digits is 141087744, while the sum is 71.

The spelling of 133998618383117 in words is "one hundred thirty-three trillion, nine hundred ninety-eight billion, six hundred eighteen million, three hundred eighty-three thousand, one hundred seventeen".