Base | Representation |
---|---|
bin | 10011011111111110011… |
… | …110010111011000110010 |
3 | 11202002210012022110211112 |
4 | 103133332132113120302 |
5 | 133423312033431114 |
6 | 2503331152313322 |
7 | 165545360533121 |
oct | 23377636273062 |
9 | 4662705273745 |
10 | 1340004202034 |
11 | 477324490293 |
12 | 197850842842 |
13 | 99491cbb4c4 |
14 | 48bdc52bab8 |
15 | 24ccae8c13e |
hex | 137fe797632 |
1340004202034 has 8 divisors (see below), whose sum is σ = 2012346243120. Its totient is φ = 669222120996.
The previous prime is 1340004202007. The next prime is 1340004202063. The reversal of 1340004202034 is 4302024000431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×13400042020342 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 389987864 + ... + 389991299.
It is an arithmetic number, because the mean of its divisors is an integer number (251543280390).
Almost surely, 21340004202034 is an apocalyptic number.
1340004202034 is a deficient number, since it is larger than the sum of its proper divisors (672342041086).
1340004202034 is an equidigital number, since it uses as much as digits as its factorization.
1340004202034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 779980024.
The product of its (nonzero) digits is 2304, while the sum is 23.
Adding to 1340004202034 its reverse (4302024000431), we get a palindrome (5642028202465).
The spelling of 1340004202034 in words is "one trillion, three hundred forty billion, four million, two hundred two thousand, thirty-four".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •