Base | Representation |
---|---|
bin | 11110011101111110100010… |
… | …110100000011001111000011 |
3 | 122120110102002002120111120010 |
4 | 132131332202310003033003 |
5 | 120030434400023043020 |
6 | 1152555222322320003 |
7 | 40140166004331624 |
oct | 3635764264031703 |
9 | 576412062514503 |
10 | 134001416221635 |
11 | 397737550580a6 |
12 | 130424571b9003 |
13 | 59a03828bba91 |
14 | 25139bb633a4b |
15 | 1075a3ea4ede0 |
hex | 79dfa2d033c3 |
134001416221635 has 16 divisors (see below), whose sum is σ = 214942322049696. Its totient is φ = 71287403286528.
The previous prime is 134001416221601. The next prime is 134001416221637. The reversal of 134001416221635 is 536122614100431.
It is not a de Polignac number, because 134001416221635 - 216 = 134001416156099 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134001416221593 and 134001416221602.
It is not an unprimeable number, because it can be changed into a prime (134001416221637) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11251162494 + ... + 11251174403.
It is an arithmetic number, because the mean of its divisors is an integer number (13433895128106).
Almost surely, 2134001416221635 is an apocalyptic number.
134001416221635 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
134001416221635 is a deficient number, since it is larger than the sum of its proper divisors (80940905828061).
134001416221635 is a wasteful number, since it uses less digits than its factorization.
134001416221635 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22502337302.
The product of its (nonzero) digits is 103680, while the sum is 39.
The spelling of 134001416221635 in words is "one hundred thirty-four trillion, one billion, four hundred sixteen million, two hundred twenty-one thousand, six hundred thirty-five".
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