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134001444103 = 592271210917
BaseRepresentation
bin111110011001100011…
…0111100010100000111
3110210212210100200000021
41330303012330110013
54143413332202403
6141320500000011
712452452324102
oct1746306742407
9423783320007
10134001444103
115191435a32a
1221b78990007
13c836bb0637
1466b2ab7739
1537442c18bd
hex1f331bc507

134001444103 has 4 divisors (see below), whose sum is σ = 136272655080. Its totient is φ = 131730233128.

The previous prime is 134001444061. The next prime is 134001444127. The reversal of 134001444103 is 301444100431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 301444100431 = 437010327917.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134001444103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134001444163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1135605400 + ... + 1135605517.

It is an arithmetic number, because the mean of its divisors is an integer number (34068163770).

Almost surely, 2134001444103 is an apocalyptic number.

134001444103 is a deficient number, since it is larger than the sum of its proper divisors (2271210977).

134001444103 is an equidigital number, since it uses as much as digits as its factorization.

134001444103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2271210976.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 134001444103 its reverse (301444100431), we get a palindrome (435445544534).

The spelling of 134001444103 in words is "one hundred thirty-four billion, one million, four hundred forty-four thousand, one hundred three".

Divisors: 1 59 2271210917 134001444103