Base | Representation |
---|---|
bin | 11110011101111111001101… |
… | …001000010001100001100011 |
3 | 122120110110220120110102022010 |
4 | 132131333031020101201203 |
5 | 120030442323244303430 |
6 | 1152555421003044003 |
7 | 40140222414631614 |
oct | 3635771510214143 |
9 | 576413816412263 |
10 | 134002126166115 |
11 | 39773a89879979 |
12 | 13042614b10603 |
13 | 59a0466a0067c |
14 | 2513a47a39c0b |
15 | 1075a82038cb0 |
hex | 79dfcd211863 |
134002126166115 has 64 divisors (see below), whose sum is σ = 224114277703680. Its totient is φ = 68291201848320.
The previous prime is 134002126166101. The next prime is 134002126166119. The reversal of 134002126166115 is 511661621200431.
It is not a de Polignac number, because 134002126166115 - 24 = 134002126166099 is a prime.
It is not an unprimeable number, because it can be changed into a prime (134002126166119) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 27859977 + ... + 32313813.
It is an arithmetic number, because the mean of its divisors is an integer number (3501785589120).
Almost surely, 2134002126166115 is an apocalyptic number.
134002126166115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
134002126166115 is a deficient number, since it is larger than the sum of its proper divisors (90112151537565).
134002126166115 is a wasteful number, since it uses less digits than its factorization.
134002126166115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4454692.
The product of its (nonzero) digits is 51840, while the sum is 39.
Adding to 134002126166115 its reverse (511661621200431), we get a palindrome (645663747366546).
The spelling of 134002126166115 in words is "one hundred thirty-four trillion, two billion, one hundred twenty-six million, one hundred sixty-six thousand, one hundred fifteen".
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