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134002232323439 is a prime number
BaseRepresentation
bin11110011101111111010011…
…011101001110110101101111
3122120110111011222012202202212
4132131333103131032311233
5120030443032433322224
61152555435314241035
740140225144150314
oct3635772335166557
9576414158182685
10134002232323439
11397740337964a7
121304264458617b
1359a04829bb95c
142513a57b90d0b
151075a8b507d0e
hex79dfd374ed6f

134002232323439 has 2 divisors, whose sum is σ = 134002232323440. Its totient is φ = 134002232323438.

The previous prime is 134002232323433. The next prime is 134002232323451. The reversal of 134002232323439 is 934323232200431.

It is a weak prime.

It is an emirp because it is prime and its reverse (934323232200431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134002232323439 - 216 = 134002232257903 is a prime.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 134002232323396 and 134002232323405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134002232323433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67001116161719 + 67001116161720.

It is an arithmetic number, because the mean of its divisors is an integer number (67001116161720).

Almost surely, 2134002232323439 is an apocalyptic number.

134002232323439 is a deficient number, since it is larger than the sum of its proper divisors (1).

134002232323439 is an equidigital number, since it uses as much as digits as its factorization.

134002232323439 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 559872, while the sum is 41.

The spelling of 134002232323439 in words is "one hundred thirty-four trillion, two billion, two hundred thirty-two million, three hundred twenty-three thousand, four hundred thirty-nine".