Base | Representation |
---|---|
bin | 11000111101011100… |
… | …01000111011001111 |
3 | 1021120220001110102022 |
4 | 30132232020323033 |
5 | 204420440013201 |
6 | 10053411120355 |
7 | 653033533352 |
oct | 143656107317 |
9 | 37526043368 |
10 | 13400313551 |
11 | 57571449a9 |
12 | 271b8a30bb |
13 | 13572c2c21 |
14 | 9119b2299 |
15 | 53667841b |
hex | 31eb88ecf |
13400313551 has 4 divisors (see below), whose sum is σ = 13400575992. Its totient is φ = 13400051112.
The previous prime is 13400313539. The next prime is 13400313587. The reversal of 13400313551 is 15531300431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13400313551 is a prime.
It is a super-2 number, since 2×134003135512 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13400313551.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13400313151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27080 + ... + 165933.
It is an arithmetic number, because the mean of its divisors is an integer number (3350143998).
Almost surely, 213400313551 is an apocalyptic number.
13400313551 is a deficient number, since it is larger than the sum of its proper divisors (262441).
13400313551 is an equidigital number, since it uses as much as digits as its factorization.
13400313551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 262440.
The product of its (nonzero) digits is 2700, while the sum is 26.
Adding to 13400313551 its reverse (15531300431), we get a palindrome (28931613982).
The spelling of 13400313551 in words is "thirteen billion, four hundred million, three hundred thirteen thousand, five hundred fifty-one".
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