Base | Representation |
---|---|
bin | 11000111101011100… |
… | …01110000001100001 |
3 | 1021120220002112001201 |
4 | 30132232032001201 |
5 | 204420441200213 |
6 | 10053411401201 |
7 | 653033651263 |
oct | 143656160141 |
9 | 37526075051 |
10 | 13400334433 |
11 | 5757159662 |
12 | 271b8b3201 |
13 | 13572cc595 |
14 | 9119b9b33 |
15 | 53667e6dd |
hex | 31eb8e061 |
13400334433 has 4 divisors (see below), whose sum is σ = 13432164628. Its totient is φ = 13368504240.
The previous prime is 13400334391. The next prime is 13400334461. The reversal of 13400334433 is 33443300431.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33443300431 = 619 ⋅54027949.
It can be written as a sum of positive squares in 2 ways, for example, as 2570185809 + 10830148624 = 50697^2 + 104068^2 .
It is a cyclic number.
It is not a de Polignac number, because 13400334433 - 213 = 13400326241 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13400334833) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15914466 + ... + 15915307.
It is an arithmetic number, because the mean of its divisors is an integer number (3358041157).
Almost surely, 213400334433 is an apocalyptic number.
It is an amenable number.
13400334433 is a deficient number, since it is larger than the sum of its proper divisors (31830195).
13400334433 is an equidigital number, since it uses as much as digits as its factorization.
13400334433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31830194.
The product of its (nonzero) digits is 15552, while the sum is 28.
Adding to 13400334433 its reverse (33443300431), we get a palindrome (46843634864).
The spelling of 13400334433 in words is "thirteen billion, four hundred million, three hundred thirty-four thousand, four hundred thirty-three".
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