1340040003213 has 4 divisors (see below), whose sum is σ = 1786720004288. Its totient is φ = 893360002140.

The previous prime is 1340040003209. The next prime is 1340040003233. The reversal of 1340040003213 is 3123000400431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1340040003213 - 2² = 1340040003209 is a prime.

It is a super-2 number, since 2×1340040003213² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1340040003213.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340040003233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223340000533 + ... + 223340000538.

It is an arithmetic number, because the mean of its divisors is an integer number (446680001072).

Almost surely, 2^{1340040003213} is an apocalyptic number.

It is an amenable number.

1340040003213 is a deficient number, since it is larger than the sum of its proper divisors (446680001075).

1340040003213 is an equidigital number, since it uses as much as digits as its factorization.

1340040003213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 446680001074.

The product of its (nonzero) digits is 864, while the sum is 21.

Adding to 1340040003213 its reverse (3123000400431), we get a palindrome (4463040403644).

The spelling of 1340040003213 in words is "one trillion, three hundred forty billion, forty million, three thousand, two hundred thirteen".