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1340040034143 = 32292435091589
BaseRepresentation
bin10011100000000000100…
…111000011011101011111
311202002212200201221020200
4103200000213003131133
5133423400222043033
62503334512314543
7165546304231656
oct23400047033537
94662780657220
101340040034143
114773427344a8
12197860842a53
1399499555c35
1448c031b819d
1524cce1b9013
hex138009c375f

1340040034143 has 12 divisors (see below), whose sum is σ = 1935679953480. Its totient is φ = 893329297776.

The previous prime is 1340040034139. The next prime is 1340040034213. The reversal of 1340040034143 is 3414300400431.

It is not a de Polignac number, because 1340040034143 - 22 = 1340040034139 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340040035143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2282608 + ... + 2808981.

It is an arithmetic number, because the mean of its divisors is an integer number (161306662790).

Almost surely, 21340040034143 is an apocalyptic number.

1340040034143 is a deficient number, since it is larger than the sum of its proper divisors (595639919337).

1340040034143 is a wasteful number, since it uses less digits than its factorization.

1340040034143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5120838 (or 5120835 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 1340040034143 its reverse (3414300400431), we get a palindrome (4754340434574).

The spelling of 1340040034143 in words is "one trillion, three hundred forty billion, forty million, thirty-four thousand, one hundred forty-three".

Divisors: 1 3 9 29243 87729 263187 5091589 15274767 45824301 148893337127 446680011381 1340040034143