1340040400141 has 4 divisors (see below), whose sum is σ = 1340047914400. Its totient is φ = 1340032885884.

The previous prime is 1340040400123. The next prime is 1340040400151. The reversal of 1340040400141 is 1410040400431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1340040400141 - 2¹¹ = 1340040398093 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340040400151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3482961 + ... + 3848518.

It is an arithmetic number, because the mean of its divisors is an integer number (335011978600).

Almost surely, 2^{1340040400141} is an apocalyptic number.

It is an amenable number.

1340040400141 is a deficient number, since it is larger than the sum of its proper divisors (7514259).

1340040400141 is an equidigital number, since it uses as much as digits as its factorization.

1340040400141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7514258.

The product of its (nonzero) digits is 768, while the sum is 22.

Adding to 1340040400141 its reverse (1410040400431), we get a palindrome (2750080800572).

The spelling of 1340040400141 in words is "one trillion, three hundred forty billion, forty million, four hundred thousand, one hundred forty-one".