13400405341 has 4 divisors (see below), whose sum is σ = 13401935712. Its totient is φ = 13398874972.

The previous prime is 13400405339. The next prime is 13400405357. The reversal of 13400405341 is 14350400431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13400405341 - 2¹ = 13400405339 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13400405311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 751975 + ... + 769588.

It is an arithmetic number, because the mean of its divisors is an integer number (3350483928).

Almost surely, 2^13400405341 is an apocalyptic number.

It is an amenable number.

13400405341 is a deficient number, since it is larger than the sum of its proper divisors (1530371).

13400405341 is an equidigital number, since it uses as much as digits as its factorization.

13400405341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1530370.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 13400405341 its reverse (14350400431), we get a palindrome (27750805772).

The spelling of 13400405341 in words is "thirteen billion, four hundred million, four hundred five thousand, three hundred forty-one".