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134004401341 is a prime number
BaseRepresentation
bin111110011001101001…
…0001110010010111101
3110210212222220220120121
41330303102032102331
54143420111320331
6141321043214541
712452516421556
oct1746322162275
9423788826517
10134004401341
1151915a9a128
1221b79977451
13c8376a7695
1466b324732d
1537446a7c11
hex1f3348e4bd

134004401341 has 2 divisors, whose sum is σ = 134004401342. Its totient is φ = 134004401340.

The previous prime is 134004401287. The next prime is 134004401387. The reversal of 134004401341 is 143104400431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 117080993241 + 16923408100 = 342171^2 + 130090^2 .

It is a cyclic number.

It is not a de Polignac number, because 134004401341 - 27 = 134004401213 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134004408341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67002200670 + 67002200671.

It is an arithmetic number, because the mean of its divisors is an integer number (67002200671).

Almost surely, 2134004401341 is an apocalyptic number.

It is an amenable number.

134004401341 is a deficient number, since it is larger than the sum of its proper divisors (1).

134004401341 is an equidigital number, since it uses as much as digits as its factorization.

134004401341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 134004401341 its reverse (143104400431), we get a palindrome (277108801772).

The spelling of 134004401341 in words is "one hundred thirty-four billion, four million, four hundred one thousand, three hundred forty-one".