Base | Representation |
---|---|
bin | 111110011001101001… |
… | …0001110010010111101 |
3 | 110210212222220220120121 |
4 | 1330303102032102331 |
5 | 4143420111320331 |
6 | 141321043214541 |
7 | 12452516421556 |
oct | 1746322162275 |
9 | 423788826517 |
10 | 134004401341 |
11 | 51915a9a128 |
12 | 21b79977451 |
13 | c8376a7695 |
14 | 66b324732d |
15 | 37446a7c11 |
hex | 1f3348e4bd |
134004401341 has 2 divisors, whose sum is σ = 134004401342. Its totient is φ = 134004401340.
The previous prime is 134004401287. The next prime is 134004401387. The reversal of 134004401341 is 143104400431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 117080993241 + 16923408100 = 342171^2 + 130090^2 .
It is a cyclic number.
It is not a de Polignac number, because 134004401341 - 27 = 134004401213 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134004408341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67002200670 + 67002200671.
It is an arithmetic number, because the mean of its divisors is an integer number (67002200671).
Almost surely, 2134004401341 is an apocalyptic number.
It is an amenable number.
134004401341 is a deficient number, since it is larger than the sum of its proper divisors (1).
134004401341 is an equidigital number, since it uses as much as digits as its factorization.
134004401341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 134004401341 its reverse (143104400431), we get a palindrome (277108801772).
The spelling of 134004401341 in words is "one hundred thirty-four billion, four million, four hundred one thousand, three hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •