Base | Representation |
---|---|
bin | 111110011001101001… |
… | …0001110111110100011 |
3 | 110210212222221001101221 |
4 | 1330303102032332203 |
5 | 4143420111413011 |
6 | 141321043235511 |
7 | 12452516432653 |
oct | 1746322167643 |
9 | 423788831357 |
10 | 134004404131 |
11 | 51915aa1234 |
12 | 21b79978b97 |
13 | c8376a8a30 |
14 | 66b3248363 |
15 | 37446a8971 |
hex | 1f3348efa3 |
134004404131 has 8 divisors (see below), whose sum is σ = 144315342864. Its totient is φ = 123693880800.
The previous prime is 134004404129. The next prime is 134004404147. The reversal of 134004404131 is 131404400431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 134004404131 - 21 = 134004404129 is a prime.
It is a super-2 number, since 2×1340044041312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 134004404096 and 134004404105.
It is not an unprimeable number, because it can be changed into a prime (134004402131) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1003656 + ... + 1129306.
It is an arithmetic number, because the mean of its divisors is an integer number (18039417858).
Almost surely, 2134004404131 is an apocalyptic number.
134004404131 is a deficient number, since it is larger than the sum of its proper divisors (10310938733).
134004404131 is a wasteful number, since it uses less digits than its factorization.
134004404131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 207701.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 134004404131 its reverse (131404400431), we get a palindrome (265408804562).
The spelling of 134004404131 in words is "one hundred thirty-four billion, four million, four hundred four thousand, one hundred thirty-one".
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