13401000414201 has 4 divisors (see below), whose sum is σ = 17868000552272. Its totient is φ = 8934000276132.

The previous prime is 13401000414157. The next prime is 13401000414223. The reversal of 13401000414201 is 10241400010431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13401000414201 - 2¹³ = 13401000406009 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13401000414271) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2233500069031 + ... + 2233500069036.

It is an arithmetic number, because the mean of its divisors is an integer number (4467000138068).

Almost surely, 2^{13401000414201} is an apocalyptic number.

It is an amenable number.

13401000414201 is a deficient number, since it is larger than the sum of its proper divisors (4467000138071).

13401000414201 is an equidigital number, since it uses as much as digits as its factorization.

13401000414201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4467000138070.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 13401000414201 its reverse (10241400010431), we get a palindrome (23642400424632).

The spelling of 13401000414201 in words is "thirteen trillion, four hundred one billion, four hundred fourteen thousand, two hundred one".