13401003413041 has 4 divisors (see below), whose sum is σ = 13407647442532. Its totient is φ = 13394359383552.

The previous prime is 13401003412997. The next prime is 13401003413117. The reversal of 13401003413041 is 14031430010431.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7485674112016 + 5915329301025 = 2735996^2 + 2432145^2 .

It is a cyclic number.

It is not a de Polignac number, because 13401003413041 - 2¹³ = 13401003404849 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13401003412997 and 13401003413015.

It is not an unprimeable number, because it can be changed into a prime (13401003453041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3322011720 + ... + 3322015753.

It is an arithmetic number, because the mean of its divisors is an integer number (3351911860633).

Almost surely, 2^{13401003413041} is an apocalyptic number.

It is an amenable number.

13401003413041 is a deficient number, since it is larger than the sum of its proper divisors (6644029491).

13401003413041 is an equidigital number, since it uses as much as digits as its factorization.

13401003413041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6644029490.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13401003413041 its reverse (14031430010431), we get a palindrome (27432433423472).

The spelling of 13401003413041 in words is "thirteen trillion, four hundred one billion, three million, four hundred thirteen thousand, forty-one".