1340102321 has 2 divisors, whose sum is σ = 1340102322. Its totient is φ = 1340102320.

The previous prime is 1340102293. The next prime is 1340102327. The reversal of 1340102321 is 1232010431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 784840225 + 555262096 = 28015^2 + 23564^2 .

It is an emirp because it is prime and its reverse (1232010431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1340102321 - 2¹⁴ = 1340085937 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1340102321.

It is not a weakly prime, because it can be changed into another prime (1340102327) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670051160 + 670051161.

It is an arithmetic number, because the mean of its divisors is an integer number (670051161).

Almost surely, 2^1340102321 is an apocalyptic number.

It is an amenable number.

1340102321 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340102321 is an equidigital number, since it uses as much as digits as its factorization.

1340102321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 1340102321 is about 36607.4080071234. The cubic root of 1340102321 is about 1102.5018319840.

Adding to 1340102321 its reverse (1232010431), we get a palindrome (2572112752).

The spelling of 1340102321 in words is "one billion, three hundred forty million, one hundred two thousand, three hundred twenty-one".