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1340102441443 = 17237346950301
BaseRepresentation
bin10011100000000100010…
…101000111100111100011
311202010001001011112222011
4103200010111013213203
5133424012211111233
62503345022053351
7165550662543313
oct23400425074743
94663031145864
101340102441443
11477374989a87
1219787971a257
13994a946682c
1448c0b5c1443
1524cd48e50cd
hex138045479e3

1340102441443 has 16 divisors (see below), whose sum is σ = 1500907254336. Its totient is φ = 1189908403200.

The previous prime is 1340102441393. The next prime is 1340102441479. The reversal of 1340102441443 is 3441442010431.

It is a cyclic number.

It is not a de Polignac number, because 1340102441443 - 29 = 1340102440931 is a prime.

It is a super-2 number, since 2×13401024414432 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1340102441143) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 23446608 + ... + 23503693.

It is an arithmetic number, because the mean of its divisors is an integer number (93806703396).

Almost surely, 21340102441443 is an apocalyptic number.

1340102441443 is a deficient number, since it is larger than the sum of its proper divisors (160804812893).

1340102441443 is a wasteful number, since it uses less digits than its factorization.

1340102441443 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 46950414.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 1340102441443 its reverse (3441442010431), we get a palindrome (4781544451874).

The spelling of 1340102441443 in words is "one trillion, three hundred forty billion, one hundred two million, four hundred forty-one thousand, four hundred forty-three".

Divisors: 1 17 23 73 391 1241 1679 28543 46950301 798155117 1079856923 3427371973 18357567691 58265323541 78829555379 1340102441443