1340102969 has 2 divisors, whose sum is σ = 1340102970. Its totient is φ = 1340102968.

The previous prime is 1340102957. The next prime is 1340102971. The reversal of 1340102969 is 9692010431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1233765625 + 106337344 = 35125^2 + 10312^2 .

It is an emirp because it is prime and its reverse (9692010431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1340102969 - 2¹² = 1340098873 is a prime.

It is a super-2 number, since 2×1340102969² = 3591751935045229922, which contains 22 as substring.

Together with 1340102971, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1340162969) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670051484 + 670051485.

It is an arithmetic number, because the mean of its divisors is an integer number (670051485).

Almost surely, 2^1340102969 is an apocalyptic number.

It is an amenable number.

1340102969 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340102969 is an equidigital number, since it uses as much as digits as its factorization.

1340102969 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11664, while the sum is 35.

The square root of 1340102969 is about 36607.4168577899. The cubic root of 1340102969 is about 1102.5020096871.

The spelling of 1340102969 in words is "one billion, three hundred forty million, one hundred two thousand, nine hundred sixty-nine".