Base | Representation |
---|---|
bin | 10011100000000100011… |
… | …000000000111000100011 |
3 | 11202010001002121002220122 |
4 | 103200010120000320203 |
5 | 133424012404402131 |
6 | 2503345050230455 |
7 | 165551002153562 |
oct | 23400430007043 |
9 | 4663032532818 |
10 | 1340103200291 |
11 | 477375358129 |
12 | 197879a2542b |
13 | 994a967105b |
14 | 48c0b73bbd9 |
15 | 24cd49e4d7b |
hex | 13804600e23 |
1340103200291 has 2 divisors, whose sum is σ = 1340103200292. Its totient is φ = 1340103200290.
The previous prime is 1340103200237. The next prime is 1340103200297. The reversal of 1340103200291 is 1920023010431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1340103200291 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1340103200291.
It is not a weakly prime, because it can be changed into another prime (1340103200297) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670051600145 + 670051600146.
It is an arithmetic number, because the mean of its divisors is an integer number (670051600146).
Almost surely, 21340103200291 is an apocalyptic number.
1340103200291 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340103200291 is an equidigital number, since it uses as much as digits as its factorization.
1340103200291 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 26.
The spelling of 1340103200291 in words is "one trillion, three hundred forty billion, one hundred three million, two hundred thousand, two hundred ninety-one".
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