1340103234343 has 4 divisors (see below), whose sum is σ = 1341631289080. Its totient is φ = 1338575179608.

The previous prime is 1340103234277. The next prime is 1340103234361. The reversal of 1340103234343 is 3434323010431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1340103234343 - 2¹³ = 1340103226151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340103238343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 764026053 + ... + 764027806.

It is an arithmetic number, because the mean of its divisors is an integer number (335407822270).

Almost surely, 2^{1340103234343} is an apocalyptic number.

1340103234343 is a deficient number, since it is larger than the sum of its proper divisors (1528054737).

1340103234343 is an equidigital number, since it uses as much as digits as its factorization.

1340103234343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1528054736.

The product of its (nonzero) digits is 31104, while the sum is 31.

Adding to 1340103234343 its reverse (3434323010431), we get a palindrome (4774426244774).

The spelling of 1340103234343 in words is "one trillion, three hundred forty billion, one hundred three million, two hundred thirty-four thousand, three hundred forty-three".