134011011102500 has 60 divisors (see below), whose sum is σ = 334920318991104. Its totient is φ = 45946632372000.

The previous prime is 134011011102467. The next prime is 134011011102503. The reversal of 134011011102500 is 5201110110431.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is not an unprimeable number, because it can be changed into a prime (134011011102503) by changing a digit.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 3828868532 + ... + 3828903531.

Almost surely, 2^{134011011102500} is an apocalyptic number.

134011011102500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

134011011102500 is an abundant number, since it is smaller than the sum of its proper divisors (200909307888604).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134011011102500 is an equidigital number, since it uses as much as digits as its factorization.

134011011102500 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7657772094 (or 7657772077 counting only the distinct ones).

The product of its (nonzero) digits is 120, while the sum is 20.

Adding to 134011011102500 its reverse (5201110110431), we get a palindrome (139212121212931).

The spelling of 134011011102500 in words is "one hundred thirty-four trillion, eleven billion, eleven million, one hundred two thousand, five hundred".