1340110214111 has 2 divisors, whose sum is σ = 1340110214112. Its totient is φ = 1340110214110.

The previous prime is 1340110214101. The next prime is 1340110214143. The reversal of 1340110214111 is 1114120110431.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1340110214111 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340110214101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670055107055 + 670055107056.

It is an arithmetic number, because the mean of its divisors is an integer number (670055107056).

Almost surely, 2^{1340110214111} is an apocalyptic number.

1340110214111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340110214111 is an equidigital number, since it uses as much as digits as its factorization.

1340110214111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 20.

Adding to 1340110214111 its reverse (1114120110431), we get a palindrome (2454230324542).

The spelling of 1340110214111 in words is "one trillion, three hundred forty billion, one hundred ten million, two hundred fourteen thousand, one hundred eleven".