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134011034411 = 169531790481
BaseRepresentation
bin111110011001110101…
…1100001101100101011
3110210220110101220102212
41330303223201230223
54143423311100121
6141321441315335
712452626666142
oct1746353415453
9423813356385
10134011034411
115191980a701
1221b80035b4b
13c838b8a887
1466b4092759
15374506825b
hex1f33ae1b2b

134011034411 has 4 divisors (see below), whose sum is σ = 134011994424. Its totient is φ = 134010074400.

The previous prime is 134011034393. The next prime is 134011034447. The reversal of 134011034411 is 114430110431.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 134011034411 - 214 = 134011018027 is a prime.

It is a super-2 number, since 2×1340110344112 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134011034711) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 225710 + ... + 564771.

It is an arithmetic number, because the mean of its divisors is an integer number (33502998606).

Almost surely, 2134011034411 is an apocalyptic number.

134011034411 is a deficient number, since it is larger than the sum of its proper divisors (960013).

134011034411 is an equidigital number, since it uses as much as digits as its factorization.

134011034411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 960012.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 134011034411 its reverse (114430110431), we get a palindrome (248441144842).

The spelling of 134011034411 in words is "one hundred thirty-four billion, eleven million, thirty-four thousand, four hundred eleven".

Divisors: 1 169531 790481 134011034411