Base | Representation |
---|---|
bin | 10011100000000100111… |
… | …001100101010110110010 |
3 | 11202010001201011012102212 |
4 | 103200010321211112302 |
5 | 133424022133003214 |
6 | 2503350003012122 |
7 | 165551140025144 |
oct | 23400471452662 |
9 | 4663051135385 |
10 | 1340112000434 |
11 | 47737a318879 |
12 | 19788096a042 |
13 | 994ab43273c |
14 | 48c0c98cc94 |
15 | 24cd568253e |
hex | 13804e655b2 |
1340112000434 has 4 divisors (see below), whose sum is σ = 2010168000654. Its totient is φ = 670056000216.
The previous prime is 1340112000277. The next prime is 1340112000449. The reversal of 1340112000434 is 4340002110431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1092453492025 + 247658508409 = 1045205^2 + 497653^2 .
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 335028000107 + ... + 335028000110.
Almost surely, 21340112000434 is an apocalyptic number.
1340112000434 is a deficient number, since it is larger than the sum of its proper divisors (670056000220).
1340112000434 is an equidigital number, since it uses as much as digits as its factorization.
1340112000434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 670056000219.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 1340112000434 its reverse (4340002110431), we get a palindrome (5680114110865).
The spelling of 1340112000434 in words is "one trillion, three hundred forty billion, one hundred twelve million, four hundred thirty-four", and thus it is an aban number.
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