13401211 has 2 divisors, whose sum is σ = 13401212. Its totient is φ = 13401210.

The previous prime is 13401191. The next prime is 13401217. The reversal of 13401211 is 11210431.

13401211 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13401211 - 2¹¹ = 13399163 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13401191 and 13401200.

It is not a weakly prime, because it can be changed into another prime (13401217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700605 + 6700606.

It is an arithmetic number, because the mean of its divisors is an integer number (6700606).

Almost surely, 2^13401211 is an apocalyptic number.

13401211 is a deficient number, since it is larger than the sum of its proper divisors (1).

13401211 is an equidigital number, since it uses as much as digits as its factorization.

13401211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 13401211 is about 3660.7664498026. The cubic root of 13401211 is about 237.5279287562.

Adding to 13401211 its reverse (11210431), we get a palindrome (24611642).

The spelling of 13401211 in words is "thirteen million, four hundred one thousand, two hundred eleven".