1340122120321 has 4 divisors (see below), whose sum is σ = 1340124617152. Its totient is φ = 1340119623492.

The previous prime is 1340122120283. The next prime is 1340122120333. The reversal of 1340122120321 is 1230212210431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1340122120321 - 2¹³ = 1340122112129 is a prime.

It is a super-2 number, since 2×1340122120321² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1340122120292 and 1340122120301.

It is not an unprimeable number, because it can be changed into a prime (1340122120361) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 76821 + ... + 1638946.

It is an arithmetic number, because the mean of its divisors is an integer number (335031154288).

Almost surely, 2^{1340122120321} is an apocalyptic number.

It is an amenable number.

1340122120321 is a deficient number, since it is larger than the sum of its proper divisors (2496831).

1340122120321 is an equidigital number, since it uses as much as digits as its factorization.

1340122120321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2496830.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 1340122120321 its reverse (1230212210431), we get a palindrome (2570334330752).

The spelling of 1340122120321 in words is "one trillion, three hundred forty billion, one hundred twenty-two million, one hundred twenty thousand, three hundred twenty-one".