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134012212343 = 1013132292411
BaseRepresentation
bin111110011001111000…
…0000001010001110111
3110210220112121202020222
41330303300001101313
54143424111243333
6141321522444555
712452643003302
oct1746360012167
9423815552228
10134012212343
115191a4446a9
1221b8050375b
13c8391b0a89
1466b42bbb39
1537451ec298
hex1f33c01477

134012212343 has 4 divisors (see below), whose sum is σ = 134144505768. Its totient is φ = 133879918920.

The previous prime is 134012212333. The next prime is 134012212351. The reversal of 134012212343 is 343212210431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134012212343 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134012212333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 66145193 + ... + 66147218.

It is an arithmetic number, because the mean of its divisors is an integer number (33536126442).

Almost surely, 2134012212343 is an apocalyptic number.

134012212343 is a deficient number, since it is larger than the sum of its proper divisors (132293425).

134012212343 is a wasteful number, since it uses less digits than its factorization.

134012212343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 132293424.

The product of its (nonzero) digits is 3456, while the sum is 26.

Adding to 134012212343 its reverse (343212210431), we get a palindrome (477224422774).

The spelling of 134012212343 in words is "one hundred thirty-four billion, twelve million, two hundred twelve thousand, three hundred forty-three".

Divisors: 1 1013 132292411 134012212343