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13401230041 = 53252853397
BaseRepresentation
bin11000111101100011…
…01000101011011001
31021120221210000121101
430132301220223121
5204421203330131
610053442511401
7653044401343
oct143661505331
937527700541
1013401230041
115757710531
122720065561
131357554124
14911b70293
155367a9c61
hex31ec68ad9

13401230041 has 4 divisors (see below), whose sum is σ = 13654083492. Its totient is φ = 13148376592.

The previous prime is 13401230023. The next prime is 13401230093. The reversal of 13401230041 is 14003210431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6612129225 + 6789100816 = 81315^2 + 82396^2 .

It is a cyclic number.

It is not a de Polignac number, because 13401230041 - 29 = 13401229529 is a prime.

It is a super-2 number, since 2×134012300412 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13401230341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 126426646 + ... + 126426751.

It is an arithmetic number, because the mean of its divisors is an integer number (3413520873).

Almost surely, 213401230041 is an apocalyptic number.

It is an amenable number.

13401230041 is a deficient number, since it is larger than the sum of its proper divisors (252853451).

13401230041 is an equidigital number, since it uses as much as digits as its factorization.

13401230041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 252853450.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 13401230041 its reverse (14003210431), we get a palindrome (27404440472).

The spelling of 13401230041 in words is "thirteen billion, four hundred one million, two hundred thirty thousand, forty-one".

Divisors: 1 53 252853397 13401230041