Base | Representation |
---|---|
bin | 1100001100000011011110… |
… | …1011111111011100001011 |
3 | 1202110010220220202022010022 |
4 | 3003000313223333130023 |
5 | 3224031210423224233 |
6 | 44300235140011055 |
7 | 2552131012366103 |
oct | 303006753773413 |
9 | 52403826668108 |
10 | 13401232242443 |
11 | 42a7481260081 |
12 | 16052b9690a8b |
13 | 7629666997a6 |
14 | 3448a1b0c203 |
15 | 1838e4339398 |
hex | c3037aff70b |
13401232242443 has 2 divisors, whose sum is σ = 13401232242444. Its totient is φ = 13401232242442.
The previous prime is 13401232242427. The next prime is 13401232242457. The reversal of 13401232242443 is 34424223210431.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13401232242443 - 24 = 13401232242427 is a prime.
It is not a weakly prime, because it can be changed into another prime (13401232212443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700616121221 + 6700616121222.
It is an arithmetic number, because the mean of its divisors is an integer number (6700616121222).
Almost surely, 213401232242443 is an apocalyptic number.
13401232242443 is a deficient number, since it is larger than the sum of its proper divisors (1).
13401232242443 is an equidigital number, since it uses as much as digits as its factorization.
13401232242443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 13401232242443 its reverse (34424223210431), we get a palindrome (47825455452874).
The spelling of 13401232242443 in words is "thirteen trillion, four hundred one billion, two hundred thirty-two million, two hundred forty-two thousand, four hundred forty-three".
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