Base | Representation |
---|---|
bin | 11000111101100011… |
… | …01001011011111101 |
3 | 1021120221210011212111 |
4 | 30132301221123331 |
5 | 204421203430044 |
6 | 10053442534021 |
7 | 653044413403 |
oct | 143661513375 |
9 | 37527704774 |
10 | 13401233149 |
11 | 57577128a7 |
12 | 2720067311 |
13 | 1357555675 |
14 | 911b71473 |
15 | 5367aab34 |
hex | 31ec696fd |
13401233149 has 2 divisors, whose sum is σ = 13401233150. Its totient is φ = 13401233148.
The previous prime is 13401233143. The next prime is 13401233189. The reversal of 13401233149 is 94133210431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10169310649 + 3231922500 = 100843^2 + 56850^2 .
It is a cyclic number.
It is not a de Polignac number, because 13401233149 - 23 = 13401233141 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13401233149.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13401233141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700616574 + 6700616575.
It is an arithmetic number, because the mean of its divisors is an integer number (6700616575).
Almost surely, 213401233149 is an apocalyptic number.
It is an amenable number.
13401233149 is a deficient number, since it is larger than the sum of its proper divisors (1).
13401233149 is an equidigital number, since it uses as much as digits as its factorization.
13401233149 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 31.
The spelling of 13401233149 in words is "thirteen billion, four hundred one million, two hundred thirty-three thousand, one hundred forty-nine".
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