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1340130104142 = 23223355017357
BaseRepresentation
bin10011100000000101111…
…110101001001101001110
311202010002222012222001120
4103200011332221031032
5133424041301313032
62503351451021410
7165551446635504
oct23400576511516
94663088188046
101340130104142
11477389563415
12197886a3a866
13994b21009ab
1448c11142674
1524cd705b62c
hex13805fa934e

1340130104142 has 8 divisors (see below), whose sum is σ = 2680260208296. Its totient is φ = 446710034712.

The previous prime is 1340130104107. The next prime is 1340130104143. The reversal of 1340130104142 is 2414010310431.

It is a sphenic number, since it is the product of 3 distinct primes.

1340130104142 is an admirable number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340130104143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111677508673 + ... + 111677508684.

It is an arithmetic number, because the mean of its divisors is an integer number (335032526037).

Almost surely, 21340130104142 is an apocalyptic number.

1340130104142 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1340130104142 is a wasteful number, since it uses less digits than its factorization.

1340130104142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 223355017362.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 1340130104142 its reverse (2414010310431), we get a palindrome (3754140414573).

The spelling of 1340130104142 in words is "one trillion, three hundred forty billion, one hundred thirty million, one hundred four thousand, one hundred forty-two".

Divisors: 1 2 3 6 223355017357 446710034714 670065052071 1340130104142