1340130113 has 8 divisors (see below), whose sum is σ = 1531849728. Its totient is φ = 1148478624.

The previous prime is 1340130101. The next prime is 1340130137. The reversal of 1340130113 is 3110310431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1340130113 - 2¹² = 1340126017 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1340130091 and 1340130100.

It is not an unprimeable number, because it can be changed into a prime (1340130193) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 36245 + ... + 63197.

It is an arithmetic number, because the mean of its divisors is an integer number (191481216).

Almost surely, 2^1340130113 is an apocalyptic number.

It is an amenable number.

1340130113 is a deficient number, since it is larger than the sum of its proper divisors (191719615).

1340130113 is an equidigital number, since it uses as much as digits as its factorization.

1340130113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34063.

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 1340130113 is about 36607.7876004546. The cubic root of 1340130113 is about 1102.5094534217.

Adding to 1340130113 its reverse (3110310431), we get a palindrome (4450440544).

The spelling of 1340130113 in words is "one billion, three hundred forty million, one hundred thirty thousand, one hundred thirteen".